1.From the twelve people consisting of eight men and four women, will set up study groups of four people. If the group learned that there are least two men, then how many ways to form the study groups ?

2.Determine whether the following series convergent or divergent !
∑_(n=1)^∞▒n^2/n!

3.A mother has five children. Oldest child was aged 2p years, the youngest was aged p years. The three others orderly was aged 2p-2, p+2, and p+1 years. If they were average aged 17 years, so age the oldest child was ∙∙∙ years.

4.Find the solution of the initial value problem
dy/dx+y-1=t.e^(-t) ,y(0)=2

5. Statistical test value
Value Frequency
61 – 65 8
66 – 70 12
71 – 75 18
76 – 80 14
Determine the mode value of the data above!


Name : CORRY SORMIN
NIM : 08305141032

SOLVING:

1.From these problem, we known that twelve people consisting of eight men and four women, will set up group of four people which is contain at least two men. So, combination which possible to form are two men and two women, three men and woman, and only four men. We can solve it with combination formula. Many ways to form the study groups with at least two men:
= (two men, two women) + (three men, woman) + (four men)
= 8C2∙4C2 + 8C3∙4C1 + 8C4∙4C0
=8!/(8-2)!2! 4!/(4-2)!2!+8!/(8-3)!3! 4!/(4-1)!1!+8!/(8-4)!4! 4!/(4-0)!0!
=8!/6!2! 41/2!2!+8!/5!3! 4!/3!1!+8!/4!4! 4!/4!0!
=8.7.6!/6!2 4.3.2!/2!2+8.7.6.5!/5!3.2 4.3!/3!+8.7.6.5.4!/4!4.3.2 4!/4!0!
= 28 ∙ 6 + 56 ∙ 4 + 70 ∙ 1
= 168 + 224 + 70
= 462
So, many ways to form study groups were 462 ways.

2.By using the theorem in calculus, we obtain:
ρ=lim┬(n→∞)⁡〖〖(n+1)〗^2/(n+1)!〗 n!/n^2
ρ=lim┬(n→∞)〗⁡〖{〖(n+1)〗^2/(n+1)n!}.( n!/n^2) 〗
ρ=lim┬(n→∞)⁡〖〖(n+1)〗^2/((n+1).n^2 )〗
ρ=lim┬(n→∞)⁡〖(n+1)/n^2 〗
ρ= 0
So, we can conclude is a convergent series.

3.From the problem we known that were five children. Oldest child was 2p years, the youngest was aged p years and three others was aged 2p-2, p+2, and p+1 years. The average of five children were 17 years. So,
x ̅=(∑▒x_i )/n
x ̅=((2p)+(2p-2)+(p+2)+(p+1)+(p))/5
x ̅=(7p+1)/5
17= (7p+1)/5
84 = 7p
p = 12
So, age of the oldest child was 2p=2×12=24 years.

4.dy/dx+y-1=t.e^(-t)
dy/dx+y=t.e^(-t)+1 (linear differential equation)
Thus the integrating factor is
μ(t)=e^∫▒1dt
μ(t)=e^t
And on multiplying dy/dx+y=t.e^(-t)+1 by this quantity, we obtain:
e^t dy/dx+e^t y=e^t (te^(-t)+1)
e^t dy/dx+e^t y=t+e^t
the left side e^t dy/dx+e^t y=t+e^t is the derivative of ye^t. So, we can write this equation as (d(ye^t))/dt=t+e^t
And it follow by integration that
ye^t=∫▒(t+e^t )dt
ye^t=1/2 t^2+e^t+c, where c is an arbitrary constant. Therefore
y=(1/2 t^2+e^t+c)/e^t
y=1/2 t^2 e^(-t)+1+ce^(-t)
to satisfy the initial condition we substitute t=0 and y=2 and solve for c
2 = 1 + c
c = 1
we obtain the value c=1, so the solution of the given initial value problem is
y=1/2 t^2 e^(-t)+1+e^(-t)

5.Mode which is located on frequency of 18, we can using the formula
Mo=tb+(d_1/(d_1+d_2 ) )i
Tb = 70,5
d1 = 18 -12 = 6
d2 = 18 -14 = 4
i = 5
So,
Mo=70.5+6/(6+4) 5

Mo = 70,5 + 3
Mo = 73,5


By : ROCHMANIA SEPTIKASARI
NIM : 08305141005

CONTENT

Content

This book is for student and especially for the third junior high school students. This contains book are descriptions of some of the material of mathematics. It is consist of :

Chapter 1. Similarity

1.1 two plane which congruen

1.2 two plane which similar

1.3 problem solving about similarity conceps

Chapter 2

1.1 tube

1.2 cone

1.3 ball

Chapter 3 Statistics and Opportunities

3.1 statistics

3.2 opportunities

Chapter 4 Degree and root

4.1 degree

4.2 root

Chapter 5 row and line of number

5.1 numeral pattern

5.2 row of numbers

5.3 line number

This book serve by two different languages, they are Indonesian languages and English languages. That can make this book very interesting. There is a map of content to give the descriptions for students before they entering to the main lesson. To help the process of settlement of the problem, given some examples of problems and training problems. And in the end of the lesson, there are several final evaluation to give students more knowledge. Beside it, there is also a set of final exam task.

Corry Sormin

08305141032

Terms of mathematics

Oleh :CORRY SORMIN

NIM :08305141032

HP :081227219498

Berikut adalah definisi, contoh, pengertian atau penjelasan-penjelasan yang lainnya tentang istilah-istilah pada I yang dibuat oleh saudara NABIH IBRAHIM BAWAZIR, yang aku tulis dalam bahasa inggris sebagai hasil dari membuka kamus, membuka ensiklopedia, mempelajari ilmu bahasa inggris, download internet, membuka blognya pak MARSIGIT, dan juga mengikuti perkuliahan beliau di kelas. Karyaku ini dapat anda akses diblog saya http://corrysormin@gmail.com. Agar komunikasi kita bisa secara terbuka dilihat dan melibatkan orang banyak termasuk mungkin bapak dosen, maka silahkan membuat komentar di bawah artikel-artikel dari blog pak MARSIGIT http://marsigitenglish.blogspot.com

1. Membangkitkan kelas =

2. Sudut ganda = double angle

3. Hakekat matematika = mathematical truth

4. Kerucut terpancung =

In cone terpancung apply the formula-the formula:

i. d₁ = 2r₁ or r₁ = ½ d ₁
ii. d₂ = 2r₂ or r₂ = ½ d ₂
iii. L_b= πr ₁2 = ¼ πd₁2
iv. L_a= πr ₂2 = ¼ πd₂2
v. L _s= πp (r ₁+ r ₂)= ½πp (d₁+ d₂)
vi. L _p= L_b + L_a+ L _s= πp(r ₁+ r ₂) + π p(r ₁²+ r ₂²)
vii. V = π/3 t (r₁ ²+ r₂² + r ₁r₂)
r1 = fingers field lining / base / bottom of the cone terpancung

d1 = diameter of the field layer / base / bottom of the cone terpancung

r2 = fingers on the cone field terpancung

D2 = diameter of the field on the cone terpancung

t = high cone terpancung

p = length of the painter or apotema cone terpancung

Lb = broad field under / base / base cone terpancung

La = broad field of top cone terpancung

Ls = broad blanket / wrap cone terpancung

Lp = broad surface of the cone terpancung

5. Segi enam sembarang = term of six events

Random segienam said if not symmetrical;

1. uniform or not wake up the sixth side is not the same

2. folded berimpit not and does not form a two-up the same broad

6. Persamaaan diferensial = equality deferensial

7. matriks tak berdeterminan =

8. Proyeksi sudut pada bidang = projection angle in the field

9. Garis tinggi = high line

Thehigher the triangle is a line drawn from the corner of the triangle and perpendicular to the side that is in the front corner of the triangle is.

10. Turunan tingkat tinggi = derived high-level

11. Dua kurva bersinggungan = two jog kurva

12. Media pembelajaran matematika = medialearning mathematics

13. Garis bagi sudut = line for the corner

The line for a point from a corner sudutnya and divide into 2 equal parts of

The high line is drawn from a point perpendicular angle and the dihadapannya

The heavy lines are drawn from a point and corner side dihadapannya divides into two equal parts of

14. Garis berat segitiga = weight of the triangle

The weight of the triangle is a line drawn from the corner of the triangle and the two share the same long side of the front corner of the

15.Dua garis sejajar = two parallel lines

Two lines g and h said parallel if and only if the second line does not have the said line or two parallel lines if the two do not even have the extended and the distance of each point on the line to the one line that's always the same

The nature - the nature of parallel lines:

1. Through a point outside a line can pull the right one in the line r is parallel with the line
2. . If a line cut in one of two parallel lines, then it will also cut the second line

3. If a line parallel with the two lines, the second line is also parallel to one another.

16. Limas = pyramid

Pyramid is built of three-dimensional space defined by base-n terms of shape and the vertical side-triangle-shaped

17. Integral tertentu = certain integral

Used Integral is the reverse process of differentiation. Integral found following a problem in finding where the differentiation matematikawan must think how to solve the problem with solutions that berkebalikan differentiation. Symbol is the integral. The two integral and not necessarily specific. The difference is integral to have a certain limit and the limit on the bottom. Integral particular usually to find the volume of play and knowledgeable

18. Integral tak tentu = not necessarily integral

Integral is not necessarily a form of operating pengintegralan a function that produces a new function. this function has not yet certain value (in the form of a variable) so how pengintegralan a result of this function is not called is not necessarily integral

19. Akar pangkat tinggi = cube root

20. Bidang empat beraturan = four areas of uniform

SOURCE:

1. http://blogger.com
2. http://sederet.com
3. http://wikipedia.com

Hi class,...

Hi class,...
My name is corry sormin, I come from jambi. In semester, I get english one, which is teached by Mr.Marsigit. In the first meeting on tuesday 17 th february 2009, Mr.Marsigit told about his experiences when he stayed in other country. he became our inspiration for us to be an adult student, and he gave us some way to improve our competence in mathematic. He also teached us to become his followers in his blog http://marsigitenglish.blogspot.com. At this subject we will learn materials to communicate mathematic in english. Mr.marsigit said that mathematic came from behaviour, high motivation, good understanding, and good spirit. He also said, "Do not think to become a mathematician if mathematic does not being to your life so make mathematic as your object in your life, we can not enjoy mathematic if we do not give a good attitude to mathematic". I think it is unbelievable motivation.
Ok my friend, so we start to make mathematic as a part of our life!